Hello friends,

I have doubts with the cable I am using for my project. The features are:

Diameter: 0.5mm
Highest voltage: 50V
Maximum current: 0.4A
AGW34

My intention is to use it with a battery of 180mAh.

It's cable too thin?, finished burning ?.

Hi Ricardo,
I'm using Cables with a maximum diameter of 0,15mm.

Best regards
Klaus

The cable is for a maximum current of 400mA/0,4A (current of charge or discharge through the wire). This depends on the cross-section of the wire (0,057mm^2). The capacity of the battery is not from interest.

Hello, thank you very much for the help.

I've been researching the subject to get the battery intensity.

As an example.

The battery gives 4 volts and has a capacity of 70mAh.

To convert voltage to watts:

W = A x v

70mAh = 0.07A

W = 0.07 x 4
W = 0.28

For intensity:

Watts / voltios = Intensity
0.28 / 4 = 0.07 Amps

In principle the cable supports the battery current. Are these correct formulations ?.

A greeting and thanks for the support.

Hi.

your battery has a 'C' rating, that's the maximum current it will deliver
without damage to it. If that rating is 15C for example and your battery
has 70mAh capacity, then you can draw 1050mA. 15*70...

How much you draw depends on the load you hook up to it, not on the battery
(assuming that the battery is strong enough for your load)

If your load draws more than 0.4A you need bigger cable, otherwise you are ok.
for a load that follows Ohm law: I = U/R
You can just supply your load with power and put a multimeter
in between to measure the current...

mAh and mA are two totally different animals, can't just treat it as the same thing,
so your formula is right but it's use is not correct.

Georg